MCQ
The period of revolution of planet $A$ around the sun is $8$ times that of $B$. The distance of $A$ from the sun is how many times greater than that of $B$ from the sun
- A$2$
- B$3$
- ✓$4$
- D$5$
✓
Answer
Correct option: C.
$4$
c
(c) $\frac{{{T_A}}}{{{T_B}}} = {\left( {\frac{{{r_A}}}{{{r_B}}}} \right)^{3/2}}$
(c) $\frac{{{T_A}}}{{{T_B}}} = {\left( {\frac{{{r_A}}}{{{r_B}}}} \right)^{3/2}}$
$ \Rightarrow 8 = {\left( {\frac{{{r_A}}}{{{r_B}}}} \right)^{3/2}}$
$ \Rightarrow {r_A} = {(8)^{2/3}}{r_B} = 4{r_B}.$
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