MCQ
The $pH$ of a $0.001\,M\,NaOH$ will be
- A$3$
- B$2$
- ✓$11$
- D$12$
$ = {10^{ - 3}}\,M \Rightarrow pOH = 3$
$pH + pOH = 14 \Rightarrow pH = 14 - 3 = 11$
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$I.$ one atom of oxygen
$II.$ one atom of nitrogen
$III.$ $1\times10^{-10}$ mole of oxygen
$IV.$ $1\times10^{-10}$ mole of copper

$\begin{matrix}
O\,\,\,\, \\
\,||\,\,\,\, \\
C{{H}_{3}}-C-Cl\xrightarrow{{{H}_{2}}S} \\
\end{matrix}$ product