MCQ
The $pH$ of a $0.001\,M\,NaOH$ will be
- A$3$
- B$2$
- ✓$11$
- D$12$
$ = {10^{ - 3}}\,M \Rightarrow pOH = 3$
$pH + pOH = 14 \Rightarrow pH = 14 - 3 = 11$
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(Molar mass of $Fe =56\, g\, mol ^{-1}$ )