MCQ
The $pH$ of a solution having $[{H^ + }] = 10 \times {10^{ - 4}}\,\,moles/litre$ will be
- A$1$
- B$2$
- ✓$3$
- D$4$
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$K_1 = 1.6 \times 10^3$ and
$[Ag(NH_3)]^+ + NH_3 \rightleftharpoons [Ag(NH_3)_2]^+$ ;
$K_2 = 6.8 \times 10^3$ .
Then formation constant of $[Ag(NH_3)_2]^+$ is :
$Fe _{3} O _{4}( s )+4 CO ( g ) \rightarrow 3 Fe ( l )+4 CO _{2}( g )$
when $4.640 \,kg$ of $Fe _{3} O _{4}$ and $2.520 \,kg$ of $CO$ are allowed to react then the amount of iron (in $g$ ) produced is $....$
[Given : Molar Atomic mass $\left( g\, mol ^{-1}\right): Fe =56$
Molar Atomic mass $\left( g \,mol ^{-1}\right): 0=16$
Molar Atomic mass $\left( g\, mol ^{-1}\right):= C =12$