MCQ
The $pH$ of a solution in which the $[{H^ + }] = 0.01,$ is
- ✓$2$
- B$1$
- C$4$
- D$3$
$pH = - \log \,\,[{10^{ - 2}}]$;$pH = 2$
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$C{H_3}C \equiv \,CC{H_3}\,\xrightarrow[{{\text{heat}}}]{{NaN{H_2}/{\text{inert solvent}}}}P$
