MCQ
The $pH $ of normal $KOH$ is
- A$1$
- B$0$
- ✓$14$
- D$7$
✓
Answer
Correct option: C.
$14$
(c)It is a strong base.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Due to covalent bonding, the transitional metals are
Value of $CFSE$, in tetrahedral complex having $3d^4$ configuration of metal ion, surrounded by weak field ligands, will be
→Match each of the reactions given in Column $I$ with the corresponding product$(s)$ given in Column $II$.
→| Column $I$ | Column $II$ |
| $(A)$ $\mathrm{Cu}+$ dil $\mathrm{HNO}_3$ | $(p)$ NO |
| $(B)$ $\mathrm{Cu}+$ conc $\mathrm{HNO}_3$ | $(q)$ $\mathrm{NO}_2$ |
| $(C)$ $\mathrm{Zn}+$ dil $\mathrm{HNO}_3$ | $(r)$ $\mathrm{N}_2 \mathrm{O}$ |
| $(D)$ $\mathrm{Zn}+$ conc $\mathrm{HNO}_3$ | $(s)$ $\mathrm{Cu}\left(\mathrm{NO}_3\right)_2$ |
| $(t)$ $ \mathrm{Zn}\left(\mathrm{NO}_3\right)_2$ |
For $K_3[Co(CN)_6]$, which of the following statement is not correct
→The shape of ${d_{xy}}$ orbital will be
→Which of the following react with benzoic acid to form ethyl benzoate
A non-metal $M$ forms $MCl_3 , M_2O_5$ and $Mg_3M_2$ but does not form $MI_5.$ Then incorrect statement regarding non-metal $M$ is
→$(Z )-2$ -Butene reacts with $Br_2/H_2O$. The resulting bromohydrin when treated with methoxide in methanol undergoes an intramolecular $S_{N^2}$ reaction. Taking into consideration the stereochemical consequences of the reaction mechanism involved, choose the final product $(s)$ of these transformations.
→During the freezing of a solution at its freezing point, which of the equilibrium exists ?
If a gas expands adiabatically from $1\,Lt.$ to $12\,Lt$. against a constant pressure of $0.75\,atm$. The $\Delta U$ of the gas is....$J$
→