Question
The $pH$ of solution having $[O{H^ - }] = {10^{ - 7}}$ is
$\because \,[O{H^ - }] = {10^{ - 7}}$
$pOH = 7$
$\therefore \,pH = 14 - 7 = 7$.
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Assume Planck's constant $( h )=6.4 \times 10^{-34}\,Js$ Speed of light $( c )=3.0 \times 10^8\,m / s$ and Avogadro's constant $\left( N _{ A }\right)=6 \times 10^{23} / mol$
$3.0$ $moles$ of $\mathrm{PCl}_{5}$ is introduced in a $1\, \mathrm{~L}$ closed reaction vessel at $380\, \mathrm{~K}$. The number of moles of $\mathrm{PCl}_{5}$ at equilibrium is $.....\,\times 10^{-3}$. (Round off to the Nearest Integer)
(Given $\ln 10=2.3, R =8.3 JK ^{-1} mol ^{-1}, \log 2=0.30$ )
Number of chiral centers generated during monochlorination in the above reaction