MCQ
The phase difference between two waves, represented by ${y_1} = {10^{ - 6}}\sin \left\{ {100t + \left( {x/50} \right) + 0.5} \right\}\ m$ , ${y_2} = {10^{ - 6}}\cos \left\{ {100t + \left( {\frac{x}{{50}}} \right)} \right\}\ m$ where $x$ is expressed in metres and $t$ is expressed in seconds, is approximately .... $radians$
- A$2.07$
- B$0.5$
- C$1.5$
- ✓$1.07$
