MCQ
The phase difference $ \phi $ is related to path difference $ \Delta x $ by :
- A$ \frac{\lambda}{\pi}\phi $
- B$ \frac{\pi}{\lambda}\phi $
- ✓$ \frac{\lambda}{2\pi}\phi $
- D$ \frac{2\pi}{\lambda}\phi $
✓
Answer
Correct option: C.
$ \frac{\lambda}{2\pi}\phi $
C
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