MCQ
The phase of a particle executing simple harmonic motion is $\frac{\pi }{2}$ when it has
- AMaximum velocity
- BMaximum acceleration
- CMaximum displacement
- ✓Both (b) and (c)
✓
Answer
Correct option: D.
Both (b) and (c)
d
(d) For $S.H.M.$ displacement $y = a\sin \omega \,t$ and acceleration $A = \, - {\omega ^2}y\sin \omega \,t$ these are maximum at $\omega \,t = \frac{\pi }{2}.$
(d) For $S.H.M.$ displacement $y = a\sin \omega \,t$ and acceleration $A = \, - {\omega ^2}y\sin \omega \,t$ these are maximum at $\omega \,t = \frac{\pi }{2}.$
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