MCQ
The photoelectric threshold wavelength for potassium (work function being $2eV$) is ........... $nm$
  • A
    $310 $
  • $620 $
  • C
    $1200 $
  • D
    $2100 $

Answer

Correct option: B.
$620 $
b
(b) $\lambda = \frac{{12375}}{{{W_0}}} = \frac{{12375}}{2} = 6187.5{Å}$$ = 620\;nm$

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