- AThe energy of activation
- BThe rate constant of the reaction
- CThe order of reaction
- ✓The energy of activation as well as frequency factor
$\log k=\log A-\frac{E_a}{2.303} \cdot \frac{1}{T}$
Plot of $\log k\,vs\, \frac{1}{ T }$ is a straight line.
Slope $=-\frac{ E _{ a }}{2.303 R }$
Intercept $=\log A$
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$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,}\\
{\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{C{H_3} - C - CH = C{H_2}}\\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow{{{H_2}O/{H^ \oplus }}}$ $\mathop A\limits_{{\rm{(major)}}} $ + $\mathop B\limits_{{\rm{(minor)}}} $
The major product is
$\frac{2}{3} Al_2O_3 \rightarrow \frac{4}{3} Al + O_2,\,$ $\Delta G = +966\,kJ\,mol$
The potential difference needed for electrolytic reduction of $Al_2O_3$ at $500^o C$ is at least ...... $V$.