- A$14$
- ✓$7$
- C$0$
- DNone of these
$\quad\quad\quad\quad H _2 O == CH ^{+}+{ }^{-} OH$
At $pOH\quad\,7 \quad\quad\quad 10^{-7} \quad\quad 10^{-7}$
If $pOH =14 \rightarrow$ solution is highly basic, the conc. of $- OH$ will be very high and due to common ion effect, the reaction goes back ward and $\alpha$ will decrease.
If $pOH =0 \rightarrow$ solution is highly aicidic, the concentration of $H ^{+}$ will be very high and due to common ion effect, the reaction moves in back ward direction.
$\therefore \quad$ At $pOH =7$, maximum dissociation.
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$\mathop {{H_3}C\mathop C\limits^ \ominus {H_2}}\limits_{(i)} \,,$$\mathop {{H_2}C = \mathop C\limits^ \ominus H}\limits_{(ii)} $ and $\mathop {H - C \equiv \mathop C\limits^ \ominus }\limits_{(iii)} $
is in the order of

Statement $I:$- In redox titration, the indicators used are sensitive to change in $pH$ of the solution.
Statement $II:$- In acid-base titration, the indicators used are sensitive to change in oxidation potential.
In the light of the above statements, choose the most appropriate answer from the options given below