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STD 11 - rectangular cartensian co-ordinates — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsSTD 11 - rectangular cartensian co-ordinates1 Mark
MCQ
The point on $y$-axis equidistant from the points $(3, 2)$ and $(-1, 3)$ is
  • A
    $(0, -3)$
  • ✓
    $(0, -3/2)$
  • C
    $(0, 3/2)$
  • D
    $(0, 3)$
✓

Answer

Correct option: B.
$(0, -3/2)$
b
(b) Point on y-axis is $(0, b)$, therefore by given condition ${(0 - 3)^2} + {(b - 2)^2} = {(0 + 1)^2} + {(b - 3)^2}$

$ \Rightarrow \,\,9 + {b^2} + 4 - 4b = 1 + {b^2} + 9 - 6b\,\, \Rightarrow \,\,b = - \frac{3}{2}$
Hence the point is $\left( {0,\, - \frac{3}{2}} \right)$.

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