midpoint of $A B$. Find in terms of $\bar{a}, \bar{b}$ and $\bar{c}$ the vector $\overline{P C}$
$\therefore \bar{p}==\frac{\bar{a}+\bar{b}}{2}$, where $\bar{p}$ is the position vector of $P$.
Now, $\overline{\mathrm{PC}}=\bar{c}-\bar{p}=\bar{c}-\frac{1}{2}(\bar{a}+\bar{b})$
$=-\frac{1}{2}(\bar{a}+\bar{b})+\bar{c}=-\frac{1}{2}-\frac{1}{a}-\frac{b}{2}+\bar{c}$.
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