MCQ
The positive integer just greater than $(1 + 0.0001)^{10000}$ is
- A$4$
- B$5$
- C$2$
- ✓$3$
${(1 + 0.0001)^{10000}} < 3$ (By putting $n = 10000$)
Also ${(1 + 0.0001)^{10000}} = 1 + 10000 \times {10^{ - 4}}+ \frac{{10000 \times 9999}}{{2!}} \times {10^{ - 8}} + ......$upto $10001$ terms
$ \Rightarrow {(1 + 0.0001)^{10000}} > 2$.
Hence $3$ is the positive integer just greater than ${(1 + 0.0001)^{10000}} > 2$
Hence $(d)$ is the correct option.
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