MCQ
The potassium ferrocyanide solution gives Prussian blue colour, when added to :
  • A
    $\mathrm{CoCl}_{3}$
  • B
    $\mathrm{FeCl}_{2}$
  • C
    $\mathrm{CoCl}_{2}$
  • $\mathrm{FeCl}_{3}$

Answer

Correct option: D.
$\mathrm{FeCl}_{3}$
d
$\left.\mathrm{FeCl}_{3}+\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] \rightarrow \mathrm{Fe}_{4}[\mathrm{Fe}(\mathrm{CN})]_{6}\right]_{3}$

$\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad$Prussian blue

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Haemoglobin is 
One mole of an ideal gas is allowed to expand reversibly and adibatically from a temperature of ${27\,^o}C$. If the work done during the process is $3\,kJ$, then final temperature of the gas is ......$K$  $({C_V} = 20\,J/K)$
In a period from $Li$ to $F$, ionization potential
When equal weights of the two fertilizers, urea and ammonium sulphate are taken, urea contains
The main reason for not using a mercury electrolytic cell in $NaOH$ manufacture is that
The major product of the following reaction is
A button cell used in watches function as following.

$Zn_{(s)} + Ag_2O_{(s)} + H_2O_{(l)} \rightleftharpoons  $$2Ag_{(s)} + Zn^{2+}_{(aq)}+ 2OH^-_{(aq)}$

If half cell potentials are

$Zn^{2+}_{(aq)} + 2e^- \rightarrow Zn_{(s)}\,;\,\, E^o = - 0.76\, V$

$Ag_2O_{(s)} + H_2O_{(l)} + 2e^- \rightarrow 2Ag_{(s)} + 2OH^-_{(aq)}\,,$$E^o = 0.34\, V$

The cell potential will be ........... $V.$

During change of $O_2$ to $O_2^-$  ion, the electron adds on which one of the following orbitals
Ethyl bromide can be converted into ethyl alcohol by
Upon heating $KClO_3$ in the presence of catalytic amount of $MnO_2$, a gas $W$ is formed. Excess amount of $W$ reacts with white phosphorus to give $X$. The reaction of $X$ with $HNO_3$ gives $Y$ and $Z$.

($1$)  $W$ and $\mathbf{X}$ are, respectively

$[A]$ $O_3$ and $P_4 O_6$   $[B]$ $O_2$ and $P_4 O_6$   $[C]$ $O_2$ and $P_4 O_{10}$    $[D]$ $O_3$ and $P_4 O_{10}$

($2$) $Y$ and $Z$ are, respectively

$[A]$ $N_2 O_3$ and $\mathrm{H}_3 \mathrm{PO}_4$

$[B]$ $N_2 O_5$ and $\mathrm{HPO}_3$

$[C]$ $N_2 O_4$ and $HPO_3$

$[D]$ $N_2 O_4$ and $H_3 PO_3$

Give the answer of quetion ($1$) and ($2$)