Question
The potential difference between the plates of a parallel plate capacitor is changing at the rate of $10^6\, V/s$. If the capacitance is $2\,\mu F$, the displacement current in the dielectric of the capacitor will be......$A$

Answer

$i_{d}=i_{c}=\frac{d q}{d t}=\frac{d}{d t}(C V)$

$=\mathrm{C} \frac{\mathrm{dv}}{\mathrm{dt}}$

$=2 \times 10^{-6} \times 10^{6}$

$=2 \mathrm{\,A}$

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