Question
The potential difference between the terminals of an electric heater is 60 V when it draws a current of 4 A from the source. What current will the heater draw, if the potential difference is increased to 120 V ?

Answer

We are given, potential difference $V=60 V$, current $I=4 A$.
According to the Ohm's law, resistance of heater coil $R=\frac{V}{I}=\frac{60 V}{4 A}=15 \Omega$.
When the potential difference is increased to 120 V the current is given by
$
\text { current }=\frac{V}{R}=\frac{120 V}{15 \Omega}=8 A .
$
Thus, the current through the heater becomes

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