Question
The potential difference between the terminals of an electric heater is 60 V When it draws a current of 4 A from the Source. What current will the heater draw if the potential difference is increased to 120 V ?

Answer

To solve this problem, we'll use Ohm's Law, which states that resistance $(R)$ is equal to potential difference ( $V$ ) divided by current ( $I$ ). The resistance of the heater remains constant.Step 1: Calculate the resistance of the heater.Using the initial conditions:
- Potential Difference $\left(V \_1\right)=60$ textV
- Current $\left(I \_1\right)=4$ text $A$
$\begin{array}{l}R= \\ \text { fracV_1I_1 = } \\ \text { frac60textV4text } A=15, \\ \text { Omega }\end{array}$
$\begin{array}{l}
I \_2= \\
\text { fracV_2R }= \\
\text { frac1 } 20 \text { textV15, Omega }=8 \\
\text { text } A
\end{array}$
The heater will draw a current of 8 A when the potential difference is increased to 120 V .

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