MCQ
The potential energy of electron in third excited state of $He^+$ ion is ............. $\mathrm{eV}$
- A$-12.08$
- B$-3.4$
- ✓$-6.8$
- D$-1.7$
$\therefore \quad \mathrm{P.E.}=2 \times \mathrm{E}_{4}=-6.8 \,\mathrm{eV}$
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(Round off to the Nearest Integer)