The potential gradient along the length of a uniform wire is $10\,volt/metre$. $B$ and $C$ are the two points at $30\,cm$ and $60\,cm$ point on a meter scale fitted along the wire. The potential difference between $B$ and $C$ will be ............. $volt$
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Potential gradient $=$ Change in voltage per unit length
$10 = \frac{{{V_2} - {V_1}}}{{30/100}} \Rightarrow {V_2} - {V_1} = 3\,volt$
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