MCQ
The power of sound from the speaker of a radio is $20$ milli watt by turning the knob of the  volume control the power of the sound is increased to $400$ milli watt. The power  increase in decibles as compared to the original power is ..... $dB$
  • $13$
  • B
    $10$
  • C
    $20$
  • D
    $800$

Answer

Correct option: A.
$13$
a
$\mathrm{SL}_{2}-\mathrm{SL}_{1}=10 \log \frac{\mathrm{I}_{2}}{\mathrm{I}_{1}}=10 \log \frac{\mathrm{P}_{2}}{\mathrm{P}_{1}}=10 \log \frac{400}{20}$

$=13 \mathrm{\,dB}$

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