- ✓${C^{12}}$
- B${O^{16}}$
- C${H^1}$
- D${C^{13}}$
The atomic mass is very small in the numerical values that's why it is calculated on the basis of comparison with the mass of carbon-$12$ isotope.
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$ \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}\left(\mathrm{NO}_2\right)-\mathrm{COOH} $
$ \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CHBr}-\mathrm{CH}_2-\mathrm{CH}_3 $
$ \mathrm{CH}_3-\mathrm{CH}(\mathrm{I})-\mathrm{CH}_2-\mathrm{NO}_2 $
$ \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}(\mathrm{OH})-\mathrm{CH}_2 \mathrm{OH} $
$ \mathrm{CH}_3-\mathrm{CH}-\mathrm{CH}(\mathrm{I})-\mathrm{C}_2 \mathrm{H}_5 $
From above data what is the molecular mass of $CH_4$ containing all isotopes of carbon but hydrogen on ${}_1^1 H$ ................ $\mathrm{u}$ (Given that atomic mass of hydrogen $= 1.008$)