MCQ
The principal reason that the melting point of $NaF$ is much higher then that of $RbBr$ is that
  • A
    the two crystals are not isomorphs
  • B
    the molar mass of $NaF$ is smaller than that of $RbBr$
  • C
    the bond in $RbBr$ has more covalent character than that the bond in $NaF$
  • the internuclear distance $(r^+ + r^-)$ is greater for $RbBr$ than for $NaF$

Answer

Correct option: D.
the internuclear distance $(r^+ + r^-)$ is greater for $RbBr$ than for $NaF$
d
$MP \propto $ lattice energy of the crystal $ \propto \frac{1}{{{r^ + } + {r^ - }}}$

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