MCQ
The principal reason that the melting point of $NaF$ is much higher then that of $RbBr$ is that
- Athe two crystals are not isomorphs
- Bthe molar mass of $NaF$ is smaller than that of $RbBr$
- Cthe bond in $RbBr$ has more covalent character than that the bond in $NaF$
- ✓the internuclear distance $(r^+ + r^-)$ is greater for $RbBr$ than for $NaF$