MCQ
The principal solution of $\cos ^{-1}\left(\cos \left(\frac{9 \pi}{4}\right)\right)$ is
  • A
    $\frac{7 \pi}{4}$
  • B
    $\frac{-\pi}{4}$
  • C
    $\frac{9 \pi}{4}$
  • D
    $\frac{\pi}{4}$

Answer

$
\begin{array}{l}
\text { (d): In }[0, \pi] \\
\cos ^{-1}\left(\cos \left(\frac{9 \pi}{4}\right)\right)=\cos ^{-1}\left(\cos \left(2 \pi+\frac{\pi}{4}\right)\right) \\
=\left(\cos ^{-1}\left(\cos \frac{\pi}{4}\right)\right)=\frac{\pi}{4}
\end{array}
$

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