MCQ
The principal solution of $\sin ^{-1}\left(\sin \left(\frac{5 \pi}{3}\right)\right)$ is
  • A
    $\frac{4 \pi}{3}$
  • B
    $\frac{5 \pi}{3}$
  • C
    $\frac{-5 \pi}{3}$
  • D
    $\frac{-\pi}{3}$

Answer

$
\begin{array}{l}
\text { (d): In }\left[\frac{-\pi}{2}, \frac{\pi}{2}\right] \\
\sin ^{-1}\left(\sin \left(\frac{5 \pi}{3}\right)\right)=\sin ^{-1}\left(\sin \left(2 \pi-\frac{\pi}{3}\right)\right) \\
=\sin ^{-1}\left(\sin \left(\frac{-\pi}{3}\right)\right)=\frac{-\pi}{3}
\end{array}
$

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