MCQ
The principal solution of the equation $\cot x=-\sqrt{3}$ is
  • A
    $\frac{\pi}{6}$
  • B
    $\frac{\pi}{3}$
  • C
    $\frac{5 \pi}{6}$
  • D
    $-\frac{5 \pi}{6}$

Answer

$\frac{5 \pi}{6}$
$\cot x=-\sqrt{3}$
$\cot x=-\cot x$
we know $\cot x$;is negative in 2nd and 4th quadrant so, we convert this 2nd or 4th
now
$\cot x=-\cot x=\cot \left(\pi-\frac{5 \pi}{6}\right)$
$x=\frac{5 \pi}{6}$
also
$\cot x=\cot \left(2 \pi-\frac{11 \pi}{6}\right)$
$x=\frac{11 \pi}{6}$
only option given is $\frac{5 \pi}{6}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free