MCQ
The principal solutions of $\sec x=\frac{2}{\sqrt{3}}$ are .....
  • A
    $\frac{\pi}{3}, \frac{11 \pi}{3}$
  • B
    $\frac{\pi}{6}, \frac{11 \pi}{3}$
  • C
    $\frac{\pi}{4}, \frac{11 \pi}{3}$
  • D
    $\frac{\pi}{6}, \frac{11 \pi}{3}$

Answer

$\sec x=\frac{2}{\sqrt{3}}$
$\cos x=\frac{\sqrt{3}}{2}=\frac{\cos \pi}{6}=\cos (2 \pi-\pi 6)$
$\frac{\pi}{6}, \frac{11 \pi}{6}$

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