MCQ
The probability distribution of a discrete random variable $X$ is given below :
$X$0123
$P(X)$$\frac{4}{k}$$\frac{6}{k}$$\frac{4}{k}$$\frac{2}{k}$
The value of $k$ is
  • A
    8
  • 16
  • C
    32
  • D
    48

Answer

Correct option: B.
16
(b) : We have $\Sigma P(X)=1$
$
\Rightarrow \frac{4}{k}+\frac{6}{k}+\frac{4}{k}+\frac{2}{k}=1 \Rightarrow \frac{16}{k}=1 \quad \Rightarrow \quad k=16
$

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