Question
The probability distribution of a discrete random variable $X$ is given below :
$X$2345
$P(X)$$\frac{5}{k}$$\frac{7}{k}$$\frac{9}{k}$$\frac{11}{k}$
The value of $k$ is

Answer

(c) : We have, $\Sigma P(X)=1$
$
\Rightarrow \frac{5}{k}+\frac{7}{k}+\frac{9}{k}+\frac{11}{k}=1 \Rightarrow \frac{32}{k}=1 \Rightarrow k=32
$

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