Question
The probability distribution of random variable X is given below:
$\text{X}$
$0$
$1$
$2$
$3$
$\text{P}(\text{X})$
$\text{k}$
$\frac{\text{k}}{2}$
$\frac{\text{k}}{4}$
$\frac{\text{k}}{8}$
Find $\text{P}(\text{X}\leq2)+\text{P}(\text{X}>2)$

Answer

$\text{P}(\text{X}\leq2)+\text{P}(\text{X}>2)$
$=\text{P}(0)+\text{P}(1)+\text{P}(2)+\text{P}(3)$
$=1$

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