The probability that a leap year will have 53 sundays is: - Vidyadip

MCQ

The probability that a leap year will have 53 sundays is:

A
$\frac17$
B
$\frac27$
C
$\frac57$
D
$\frac67$

✓

Answer

$\frac27$

Solution:

A leap year has 52 weeks and 2 days.

The 53^rd Sunday will be from these extra two days

These 2 days can be (Sunday, Monday) or (Mon, Tue) or (Tue, Wed).....(Sat, Sun)

There are 7 possibilities for these 2 days

Out of which Sunday is coming in 2 possibilities.

$\therefore$ P(2 sundays in leap year) $=\frac27$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Probability→Probability — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

Choose the correct answer from the given four options.

If $\text{P}(\text{A}\cap\text{B})=\frac{7}{10},$ and $\text{P}(\text{B})=\frac{17}{20},$ then $\text{P}\Big(\frac{\text{A}}{\text{B}}\Big)$ equas:

The differential equation satisfied by the function $y = \sqrt {\sin x + \sqrt {\sin x + \sqrt {\sin x + .....\infty } } } $, is

$\int\frac{\text{x}}{4+\text{x}^4}\text{ dx}$ is equal to:

$\frac{1}{4}\tan^{-1}\text{x}^2+\text{C}$
$\frac{1}{4}\tan^{-1}\Big(\frac{\text{x}^2}{2}\Big)$
$\frac{1}{2}\tan^{-1}\Big(\frac{\text{x}^2}{2}\Big)$
none of these.

Let $f : R \rightarrow R$ be defined as $f(x)\, = \,{3^{ - \left| x \right|}} - {3^x} + \operatorname{sgn} ({e^{ - x}}) + 2$

(whre $\operatorname{sgn} x$ denotes signum function of $x$). Then
which one of the following is correct ?

If $y(t)$ is a solution of $(1 + t)\frac{{dy}}{{dt}} - ty = 1$ and $y(0) = - 1,$ then $y(1)$ is equal to

If $A = \left[ {\begin{array}{*{20}{c}}1&2&3\\1&4&9\\1&8&{27}\end{array}} \right]$, then the value of $|adj\,\,A|$is

Let $f(\theta ) = \sin \theta (\sin \theta + \sin 3\theta )$, then $f(\theta )$

Let $J=\int_0^1 \frac{x}{1+x^8} d x$

Consider the following assertions:

$I$. $J>\frac{1}{4}$

$II$. $J<\frac{\pi}{8}$ Then,

The area of the region bounded by the curve $y = x^3,$ and the lines, $y = 8,$ and $x = 0,$ is

Solution of the following $LP$ problem

Maximize $z=2 x+6 y$ subject to $-x+y \leq 1,2 x+y \leq 2$ and $x \geq 0, y \geq 0 "$ is $.......$