MCQ
The probability that a non leap year selected at random will have 53 Sundays is
  • A
    $0$
  • $\frac{1}{7}$
  • C
    $\frac{2}{7}$
  • D
    $\frac{3}{7}$

Answer

Correct option: B.
$\frac{1}{7}$
(B)
In a non leap year, there are 365 days which has 52 weeks and 1 day.
$\therefore \quad P(53$ Sundays $)-\frac{1}{7}$

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