MCQ
The probability that a randomly chosen $5-digit$ number is made from exactly two digits is
- A$\frac{121}{10^{4}}$
- B$\frac{150}{10^{4}}$
- ✓$\frac{135}{10^{4}}$
- D$\frac{134}{10^{4}}$
Now, number of 5 -digit numbers containing both digits $=2^{5}-2$
Second Case: Choose one non-zero \& one zero as digit ${ }^{9} C _{1}$
Number of 5 -digit numbers containg one non zero and one zero both $=\left(2^{4}-1\right)$ Required prob.
$=\frac{\left({ }^{9} C _{2} \times\left(2^{5}-2\right)+{ }^{9} C _{1} \times\left(2^{4}-1\right)\right)}{9 \times 10^{4}}$
$=\frac{36 \times(32-2)+9 \times(16-1)}{9 \times 10^{4}}$
$=\frac{4 \times 30+15}{10^{4}}=\frac{135}{10^{4}}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(A)$ $S Q_1=2$
$(B)$ $Q _1 Q _2=\frac{3 \sqrt{10}}{5}$
$(C)$ $PQ _1=3$
$(D)$ $SQ _2=1$