The probability that an ordinary or a non-leap year has 53 sunday… - Vidyadip

MCQ

The probability that an ordinary or a non-leap year has $53$ sunday, is

A
$\frac{2}{7}$
✓
$\frac{1}{7}$
C
$\frac{3}{7}$
D
None of these

✓

Answer

Correct option: B.

$\frac{1}{7}$

b
(b) In a non-leap year, we have $365$ days $i.e.,$ $52$ weeks and one day.

So, we may have any day of seven days.

Therefore, $53$ Sunday, required probability $= \frac{1}{7}$.

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