MCQ
The product of the reaction will be :


- A$C_6H_5-CH =CH-COOH$
- B

- C

- ✓






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$1.$ Boron is approximately $sp^3$ hybridized
$2.$ $B-H-B$ angle is $180^o$
$3.$ There are two terminal $B-H$ bonds for each boron atom
$4.$ There are only $12$ bonding electrons available
Of these statements
