MCQ
The Product $\sqrt[3]{2}\times\sqrt[4]{2}\times\sqrt[12]{32}$ is equal to:
- A$\sqrt[12]{2}$
- B$2$
- C$\sqrt[12]{32}$
- D$\sqrt{2}$
✓
Answer
- $2$
Solution:
$\sqrt[3]{2}\times\sqrt[4]{2}\times\sqrt[12]{32}$
$=\sqrt[3]{2}\times\sqrt[4]{2}\times\sqrt[12]{(2)^5}$
$=(2)^{\frac{1}{3}}\times(2)^{\frac{1}{4}}\times(2)^{\frac{5}{15}}$
$=(2)^{\frac{1}{3}+\frac{1}{4}+\frac{5}{12}}$
$=(2)^{\frac{4+3+5}{12}}$
$=(2)^{\frac{12}{12}}$
$=2$
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