MCQ
The quadratic equation with real coefficients whose one root is $7 + 5i$, will be
  • ${x^2} - 14x + 74 = 0$
  • B
    ${x^2} + 14x + 74 = 0$
  • C
    ${x^2} - 14x - 74 = 0$
  • D
    ${x^2} + 14x - 74 = 0$

Answer

Correct option: A.
${x^2} - 14x + 74 = 0$
a
(a) Let $\alpha = 7 + 5i$, then its conjugate $\beta = 7 - 5i$, so required equation is given by ${x^2} - (\alpha + \beta )x + \alpha \beta = 0$

==> ${x^2} - (14)x + (49 + 25) = 0$

==> ${x^2} - 14x + 74 = 0$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The triangle $PQR$  of area $ 'A' $ is inscribed in the parabola $ y^2 = 4ax $ such that the vertex $P$  lies at the vertex of the parabola and the base $QR$  is a focal chord. The modulus of the difference of the ordinates of the points $Q$ and $R $ is :
If $f(x)=\left|\begin{array}{ccc}\cos (2 x) & \cos (2 x) & \sin (2 x) \\ -\cos x & \cos x & -\sin x \\ \sin x & \sin x & \cos x\end{array}\right|$, then

$[A]$ $f^{\prime}(x)=0$ at exactly three points in $(-\pi, \pi)$

$[B]$ $f^{\prime}(x)=0$ at more than three points in $(-\pi, \pi)$

$[C]$ $f(x)$ attains its maximum at $x=0$

$[D]$ $f(x)$ attains its minimum at $x=0$

The straight line $x + 2y = 1$ meets the coordinate axes at $A$ and $B$. A circle is drawn through $A, B$ and the origin. Then the sum of perpendicular distances from $A$ and $B$ on the tangent to the circle at the origin is
The line $y = mx$ bisects the area enclosed by the curve $y = 1 + 4x - x^2\,\, \&$ the lines $x = 0, x = \frac{3}{2} \& \,\,y = 0.$ Then the value of $m$ is:
The true solution set of the inequality,

$\sqrt {5\,x\,\, - \,\,6\,\, - \,\,{x^2}} \,\, + \,\,\frac{\pi }{2}\,\,\int\limits_0^x {} $$dz > x \int\limits_0^\pi  {} sin^2 x \,dx$ is :

The line $x =8$ is the directrix of the ellipse $E: \frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ with the corresponding focus $(2,0)$. If the tangent to $E$ at the point $P$ in the first quadrant passes through the point $(0,4 \sqrt{3})$ and intersects the $x$-axis at $Q$, then $(3PQ)^2$ is equal to $........$
If $p$ and $q$ are roots of $6x^2 + 10x + 1 = 0$, then the value of $[tan^{-1} p + tan^{-1} q]$ is {where $[x]$ denotes greatest integer less than or equal to $x$}
$\mathop {\lim }\limits_{x \to 0} \,\,\frac{{{{\log }_e}(1 + x)}}{{{3^x} - 1}} = $
$\mathop {Limit}\limits_{x\,\, \to \,\,4} $ $\frac{{{{(\cos \,\alpha )}^x}\, - \,\,{{(\sin \,\alpha )}^x}\, - \,\,\cos \,2\alpha }}{{x\,\, - \,\,4}}=$ 

where $0 < \alpha <$ $\frac{\pi }{2}$ 

The centre of the ellipse $4{x^2} + 9{y^2} - 16x - 54y + 61 = 0$ is