MCQ
The radical, (image) is aromatic because it has
- A$7\, p-$orbitals and $7$ unpaired electrons
- B$6\, p-$orbitals and $7\,$ unpaired electrons
- ✓$6\, p-$orbitals and $6$ unpaired electrons
- D$7\, p-$orbitals and $6$ unpaired electrons.
formation of benzene ring (Aromatic nature).
$6 \pi$ electrons and $6 p$ orbitals
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$(I)\, SF_4$ $(II)\, OSF_4$ $(III)\, H_2CSF_4$
| List $- I$ | List $- II$ |
| $(a)$ $\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}$ | $(i)$ $5.92 \,\mathrm{BM}$ |
| $(b)$ $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ | $(ii)$ $0 \,\mathrm{BM}$ |
| $(c)$ $\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}$ | $(iii)$ $4.90\, \mathrm{BM}$ |
| $(d)$ $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ | $(iv)$ $1.73\, \mathrm{BM}$ |
Choose the correct answer from the options given below.
$3,4,5-$Tribromoaniline $\underset{\text{(ii) }{{H}_{3}}P{{O}_{2}}}{\mathop{\xrightarrow{\text{(i) diazotization}}}}\,\,?$