MCQ
The radical, (image) is aromatic because it has


- A$7\, p-$orbitals and $7$ unpaired electrons
- B$6\, p-$orbitals and $7\,$ unpaired electrons
- ✓$6\, p-$orbitals and $6$ unpaired electrons
- D$7\, p-$orbitals and $6$ unpaired electrons.

formation of benzene ring (Aromatic nature).
$6 \pi$ electrons and $6 p$ orbitals
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Set $1$: $Al_2O_3 .xH_2O\, (s)$ and $OH^-(aq)$
Set $2$: $Al_2O_3 .xH_2O\, (s)$ and $H_2O\,(l)$
Set $3$: $Al_2O_3 .xH_2O\, (s)$ and $H^+(aq)$
Set $4$: $Al_2O_3 .xH_2O\, (s)$ and $NH_3(aq)$


$HSO_4^- = 1.2 \times 10^{- 2} ,H_2PO_4^- = 6.3 \times 10^{-8} ,$$HCO_3^- = 4.7 \times 10^{-11}$