MCQ
The rate constant is doubled when temperature increases from $27\,^oC$ to $37\,^oC.$ Activation energy in $kJ$ is
- A$34$
- ✓$54$
- C$100$
- D$50$
✓
Answer
Correct option: B.
$54$
b
$\log \frac{{{K_2}}}{{{K_1}}} = \frac{{{E_a}}}{{2.303R}}\left[ {\frac{1}{{{T_1}}} - \frac{1}{{{T_2}}}} \right]$
$\log \frac{{{K_2}}}{{{K_1}}} = \frac{{{E_a}}}{{2.303R}}\left[ {\frac{1}{{{T_1}}} - \frac{1}{{{T_2}}}} \right]$
If $\frac{{{K_2}}}{{{K_1}}} = 2$
$\log 2 = \frac{{{E_a}}}{{2.303 \times 8.314}}\left[ {\frac{1}{{300}} - \frac{1}{{310}}} \right]$
${E_a} = .3010 \times 2.303 \times 8.314\left( {\frac{{300 \times 310}}{{10}}} \right)$
$ = 53598.59\;J\,mo{l^{ - 1}}$
$ = 54\;kJ$.
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