MCQ
The ratio of area covered by second orbital to the first orbital is
- A$1:2$
- B$1:16$
- C$8:1$
- ✓$16:1$
$\frac{{{A_2}}}{{{A_1}}} = \frac{{n_2^4}}{{n_1^4}} = \frac{{{2^4}}}{{{1^4}}} = \frac{{16}}{1} = 16\,:1$
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