MCQ
The ratio of difference between $1^{st}$ and $2^{nd}$ Bohr orbits energy to that between $2^{nd}$ and $3^{rd}$ orbits energy is
- A$0.5$
- B$\frac{1}{3}$
- ✓$5.4$
- D$\frac{5}{27}$
$ E_{3} =-\frac{13.6}{(3)^{2}}=-{13.6}{9} $
$=-1.5 \mathrm{eV} $
$ E_{2} =-\frac{13.6}{(2)^{2}}=-{13.6}{4} $
$=-3.4 \mathrm{eV} $
$ E_{1} =-{13.6}{(1)^{2}}=-{13.6}{1} $
$=-13.6 \mathrm{eV} $
$Now E_{2}-E_{1}=(-3.4)-(-13.6) $
$=13.6-3.4=10.2 \mathrm{eV} $
$ E_{3}-E_{2} =(-1.5)-(3.4) $
$=3.4-1.5=1.9 \mathrm{eV} $
$ \therefore \quad \frac{E_{2}-E_{1}}{E_{3}-E_{2}} =\frac{10.2}{1.9}=5.36 $
$=5.4=\frac{27}{5} $
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
($R = 0.082\, L\, atm\, mol^{-1}\, K^{-1}$, Molar mass of $S = 32\, g\, mol^{-1}$, molar mass of $N = 14\, g\, mol^{-1}$)