The ratio of frequencies of fundamental harmonic produced by an open pipe to that of closed pipe having the same length is
A$3: 1$
B$1: 2$
C$2: 1$
D$1: 3$
NEET 2023, Easy
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C$2: 1$
c $\frac{n_{\text {oop }}}{ n _{\text {cop }}}=\frac{\frac{ V }{2 L }}{\frac{ V }{4 L }}$
$\Rightarrow \frac{ n _{\text {oop }}}{ n _{\text {cop }}}=\frac{2}{1}$
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