MCQ
The ratio of velocity of electron in second orbit of $He^+$ to third orbit of $B^{+4}$ is
- A$\frac{5}{3}$
- ✓$\frac{3}{5}$
- C$\frac{3}{2}$
- D$\frac{2}{3}$
✓
Answer
Correct option: B.
$\frac{3}{5}$
b
$V \propto \frac{Z}{n}$ $\frac{{V_2^{H{e^ + }}}}{{V_3^{{B^{ + 4}}}}} = \frac{{2/2}}{{5/3}} = \frac{3}{5}$
$V \propto \frac{Z}{n}$ $\frac{{V_2^{H{e^ + }}}}{{V_3^{{B^{ + 4}}}}} = \frac{{2/2}}{{5/3}} = \frac{3}{5}$
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