MCQ
The rational number $\frac{110}{-132}$ when reduced to standard form is
  • A
    $\frac{10}{-12}$
  • B
    $\frac{5}{-6}$
  • C
    $\frac{-75}{6}$
  • D
    $\frac{110}{-132}$

Answer

$\frac{110}{-132}=\frac{110 \div(-22)}{-132 \div(-22)}=\frac{-5}{6}$ $\text{(c)}$

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