MCQ
The reaction of ${K_2}C{r_2}{O_7}$ with $NaCl$ and conc. ${H_2}S{O_4}$ gives
- A$CrC{l_3}$
- B$CrOC{l_2}$
- ✓$Cr{O_2}C{l_2}$
- D$C{r_2}{O_3}$
✓
Answer
Correct option: C.
$Cr{O_2}C{l_2}$
c
(c)$NaCl + {H_2}S{O_4} + {K_2}C{r_2}{O_7}\, \to $
$\mathop {Cr{O_2}C{l_2} + }\limits_{{\rm{Chromyl chloride}}} {K_2}S{O_4} + N{a_2}S{O_4}$
(c)$NaCl + {H_2}S{O_4} + {K_2}C{r_2}{O_7}\, \to $
$\mathop {Cr{O_2}C{l_2} + }\limits_{{\rm{Chromyl chloride}}} {K_2}S{O_4} + N{a_2}S{O_4}$
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