MCQ
The reaction of one mol of bromine with ethyne yields :
- A$ \mathrm{BrCH}_2-\mathrm{CH}_2 \mathrm{Br} $
- ✓$ \mathrm{BrCH}=\mathrm{CHBr} $
- C$ \mathrm{Br}_2 \mathrm{CH}-\mathrm{CHBr}_2 $
- D$ \mathrm{CH}_3-\mathrm{CH}_2 \mathrm{Br} $
✓
Answer
Correct option: B.
$ \mathrm{BrCH}=\mathrm{CHBr} $
Halogens, especially chlorine and bromine on reaction with alkynes readily produces tetra $-$ halogen derivatives of alkane. The reaction is carried out in inert solvent like carbon tetrachloride.
Due to the presence of two $n-$ bonds, each molecule of the alkyne can react with two molecules of the halogen.
One mole of Bromine with ethyne gives $1, 2-$ dibromoethene.
Due to the presence of two $n-$ bonds, each molecule of the alkyne can react with two molecules of the halogen.
One mole of Bromine with ethyne gives $1, 2-$ dibromoethene.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The number of $- CH _2$ - (methylene) groups in the product formed from the following reaction sequence is. . . . . . .
→Sodium oxide reacts with water to produce sodium hydroxide. $20.0\, \mathrm{~g}$ of sodium oxide is dissolved in $500\, \mathrm{~mL}$ of water. Neglecting the change in volume, the concentration of the resulting $\mathrm{NaOH}$ solution is $........\times \quad 10^{-1} \quad$ $M.$ (Nearest integer)
→[Atomic mass $: \mathrm{Na}=23.0, \mathrm{O}=16.0, \mathrm{H}=1.0]$
Among I-A elements, which element is gas at room temperature?
Isomerism in saturated hydrocarbons is due to
$X$ compound reacts with $\text{Na}$ to give $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_3$. The compound $X$ is :
→Silver acetylide when heated with $HCl$ gives
→Element having atomic number $33$ belongs to this group?
→Consider the following reaction:
→$3 \mathrm{PbCl}_2+2\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \rightarrow \mathrm{Pb}_3\left(\mathrm{PO}_4\right)_2+6 \mathrm{NH}_4 \mathrm{Cl}$
If $72 \mathrm{mmol}$ of $\mathrm{PbCl}_2$ is mixed with $50 \mathrm{mmol}$ of$\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4$, then amount of $\mathrm{Pb}_3\left(\mathrm{PO}_4\right)_2$ formed is......... mmol. (nearest integer)
After the completion of $\text{np6}$ electronic configuration, the next orbital will be filled by :
→Which of the following does not have rock salt type structure?