MCQ
The reaction of propene with $HOCl (Cl_2 + H_2O)$ proceeds through the intermediate :
- A$CH_3 -CH(OH)-CH_2^+$
- B$CH_3 -CHCl-CH_2^+$
- C$CH_3 -CH^+ -CH_2 -OH$
- ✓$CH_3 -CH^+ -CH_2 -Cl$
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$(i)$ $n\, = 4, l\, = 1$ $(ii)$ $n\, = 4, l\, = 0$
$(iii)$ $n\, = 3, l\, = 2$ $(iv)$ $n\, = 3, l\, = 1$
The sequence representing increasing order of energy, is

$(a)\; C \;\;(b)\; O \;\;(c)\; F\;\; (d) \;Cl\;\; (e)\; Br$
$\mathrm{C}_{7} \mathrm{H}_{8} \stackrel{3 \mathrm{Cl}_{2} / \Delta}{\longrightarrow} \mathrm{A} \stackrel{\mathrm{Br}_{2} / \mathrm{Fe}}{\rightarrow} \mathrm{B} \stackrel{\mathrm{Zn} / \mathrm{HCl}}{\rightarrow} \mathrm{C}$
The product '$C$' is